13100004220013 has 8 divisors (see below), whose sum is σ = 13105143175488. Its totient is φ = 13094866162944.

The previous prime is 13100004220007. The next prime is 13100004220049. The reversal of 13100004220013 is 31002240000131.

13100004220013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13100004220013 - 2⁴ = 13100004219997 is a prime.

It is a super-2 number, since 2×13100004220013² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13100004219973 and 13100004220000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100004222013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29722256 + ... + 30159782.

It is an arithmetic number, because the mean of its divisors is an integer number (1638142896936).

Almost surely, 2^{13100004220013} is an apocalyptic number.

It is an amenable number.

13100004220013 is a deficient number, since it is larger than the sum of its proper divisors (5138955475).

13100004220013 is an equidigital number, since it uses as much as digits as its factorization.

13100004220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 449203.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13100004220013 its reverse (31002240000131), we get a palindrome (44102244220144).

The spelling of 13100004220013 in words is "thirteen trillion, one hundred billion, four million, two hundred twenty thousand, thirteen".