13100012011020 has 192 divisors, whose sum is σ = 40107533179392. Its totient is φ = 3168391680000.

The previous prime is 13100012011019. The next prime is 13100012011039. The reversal of 13100012011020 is 2011021000131.

It is a super-2 number, since 2×13100012011020² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 13100012010987 and 13100012011005.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 547716102 + ... + 547740018.

It is an arithmetic number, because the mean of its divisors is an integer number (208893401976).

Almost surely, 2^{13100012011020} is an apocalyptic number.

13100012011020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100012011020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20053766589696).

13100012011020 is an abundant number, since it is smaller than the sum of its proper divisors (27007521168372).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100012011020 is a wasteful number, since it uses less digits than its factorization.

13100012011020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25832 (or 25830 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 13100012011020 its reverse (2011021000131), we get a palindrome (15111033011151).

The spelling of 13100012011020 in words is "thirteen trillion, one hundred billion, twelve million, eleven thousand, twenty".