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1310001320002 = 2655000660001
BaseRepresentation
bin10011000100000010001…
…010011101000001000010
311122020100020121011001111
4103010002022131001002
5132430340314220002
62441450054353534
7163434024331624
oct23040212350102
94566306534044
101310001320002
11465628658a11
12191a7895b8aa
13966c015767b
1447593972c14
1524121e943d7
hex1310229d042

1310001320002 has 4 divisors (see below), whose sum is σ = 1965001980006. Its totient is φ = 655000660000.

The previous prime is 1310001319973. The next prime is 1310001320003. The reversal of 1310001320002 is 2000231000131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1134137671681 + 175863648321 = 1064959^2 + 419361^2 .

It is a super-2 number, since 2×13100013200022 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1310001320003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327500329999 + ... + 327500330002.

Almost surely, 21310001320002 is an apocalyptic number.

1310001320002 is a deficient number, since it is larger than the sum of its proper divisors (655000660004).

1310001320002 is an equidigital number, since it uses as much as digits as its factorization.

1310001320002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655000660003.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 1310001320002 its reverse (2000231000131), we get a palindrome (3310232320133).

The spelling of 1310001320002 in words is "one trillion, three hundred ten billion, one million, three hundred twenty thousand, two".

Divisors: 1 2 655000660001 1310001320002