131000133113021 has 4 divisors (see below), whose sum is σ = 132297164134044. Its totient is φ = 129703102092000.

The previous prime is 131000133112997. The next prime is 131000133113029. The reversal of 131000133113021 is 120311331000131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 125473938295225 + 5526194817796 = 11201515^2 + 2350786^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131000133113021 is a prime.

It is a super-2 number, since 2×131000133113021² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131000133112984 and 131000133113002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000133113029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 648515510360 + ... + 648515510561.

It is an arithmetic number, because the mean of its divisors is an integer number (33074291033511).

Almost surely, 2^{131000133113021} is an apocalyptic number.

It is an amenable number.

131000133113021 is a deficient number, since it is larger than the sum of its proper divisors (1297031021023).

131000133113021 is a wasteful number, since it uses less digits than its factorization.

131000133113021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1297031021022.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 131000133113021 its reverse (120311331000131), we get a palindrome (251311464113152).

The spelling of 131000133113021 in words is "one hundred thirty-one trillion, one hundred thirty-three million, one hundred thirteen thousand, twenty-one".