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13100020103 = 25935052071
BaseRepresentation
bin11000011001101001…
…00111000110000111
31020210221222222020202
430030310213012013
5203312101120403
610003522521115
7642426222302
oct141464470607
936727888222
1013100020103
11561268aaa5
12265720619b
13130a0216b1
148c3b63b39
1551a10c688
hex30cd27187

13100020103 has 4 divisors (see below), whose sum is σ = 13105074768. Its totient is φ = 13094965440.

The previous prime is 13100020097. The next prime is 13100020127. The reversal of 13100020103 is 30102000131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30102000131 = 74300285733.

It is a cyclic number.

It is not a de Polignac number, because 13100020103 - 26 = 13100020039 is a prime.

It is a super-2 number, since 2×131000201032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100020303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2523443 + ... + 2528628.

It is an arithmetic number, because the mean of its divisors is an integer number (3276268692).

Almost surely, 213100020103 is an apocalyptic number.

13100020103 is a deficient number, since it is larger than the sum of its proper divisors (5054665).

13100020103 is an equidigital number, since it uses as much as digits as its factorization.

13100020103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5054664.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13100020103 its reverse (30102000131), we get a palindrome (43202020234).

The spelling of 13100020103 in words is "thirteen billion, one hundred million, twenty thousand, one hundred three".

Divisors: 1 2593 5052071 13100020103