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131000304310331 = 235695665404797
BaseRepresentation
bin11101110010010011100010…
…100110101001100000111011
3122011211111200110001021112212
4131302103202212221200323
5114132302110400412311
61142340413050525335
736410313443101601
oct3562234246514073
9564744613037485
10131000304310331
1138816a0a680a65
12128388a0a3684b
1358133778ca6c1
14244c63cbbb871
1510229428c0c8b
hex7724e29a983b

131000304310331 has 4 divisors (see below), whose sum is σ = 136695969715152. Its totient is φ = 125304638905512.

The previous prime is 131000304310321. The next prime is 131000304310339. The reversal of 131000304310331 is 133013403000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131000304310331 - 222 = 131000300116027 is a prime.

It is a super-2 number, since 2×1310003043103312 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 5695665404797 = 131000304310331 / (1 + 3 + 1 + 0 + 0 + 0 + 3 + 0 + 4 + 3 + 1 + 0 + 3 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131000304310297 and 131000304310306.

It is not an unprimeable number, because it can be changed into a prime (131000304310339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2847832702376 + ... + 2847832702421.

It is an arithmetic number, because the mean of its divisors is an integer number (34173992428788).

Almost surely, 2131000304310331 is an apocalyptic number.

131000304310331 is a deficient number, since it is larger than the sum of its proper divisors (5695665404821).

131000304310331 is an equidigital number, since it uses as much as digits as its factorization.

131000304310331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5695665404820.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 131000304310331 its reverse (133013403000131), we get a palindrome (264013707310462).

The spelling of 131000304310331 in words is "one hundred thirty-one trillion, three hundred four million, three hundred ten thousand, three hundred thirty-one".

Divisors: 1 23 5695665404797 131000304310331