Base | Representation |
---|---|
bin | 10011000100000010010… |
… | …001010100101111010111 |
3 | 11122020100100222122201020 |
4 | 103010002101110233113 |
5 | 132430341244333421 |
6 | 2441450201132223 |
7 | 163434045542646 |
oct | 23040221245727 |
9 | 4566310878636 |
10 | 1310003121111 |
11 | 465629679133 |
12 | 191a7948a073 |
13 | 966c0638409 |
14 | 47593cc135d |
15 | 241221ecdc6 |
hex | 13102454bd7 |
1310003121111 has 4 divisors (see below), whose sum is σ = 1746670828152. Its totient is φ = 873335414072.
The previous prime is 1310003121067. The next prime is 1310003121127. The reversal of 1310003121111 is 1111213000131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310003121111 - 226 = 1309936012247 is a prime.
It is a super-2 number, since 2×13100031211112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310003121181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218333853516 + ... + 218333853521.
It is an arithmetic number, because the mean of its divisors is an integer number (436667707038).
Almost surely, 21310003121111 is an apocalyptic number.
1310003121111 is a deficient number, since it is larger than the sum of its proper divisors (436667707041).
1310003121111 is an equidigital number, since it uses as much as digits as its factorization.
1310003121111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436667707040.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 1310003121111 its reverse (1111213000131), we get a palindrome (2421216121242).
The spelling of 1310003121111 in words is "one trillion, three hundred ten billion, three million, one hundred twenty-one thousand, one hundred eleven".
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