Base | Representation |
---|---|
bin | 1011111010100001011010… |
… | …1101010010011001101010 |
3 | 1201101100110200220011222111 |
4 | 2332220112231102121222 |
5 | 3204112330443122102 |
6 | 43510023220512534 |
7 | 2521305662102254 |
oct | 276502655223152 |
9 | 51340420804874 |
10 | 13100031223402 |
11 | 41a0768121462 |
12 | 1576a59b4b74a |
13 | 740434aaa936 |
14 | 33408b292cd4 |
15 | 17ab664dccd7 |
hex | bea16b5266a |
13100031223402 has 4 divisors (see below), whose sum is σ = 19650046835106. Its totient is φ = 6550015611700.
The previous prime is 13100031223333. The next prime is 13100031223423. The reversal of 13100031223402 is 20432213000131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7271915829201 + 5828115394201 = 2696649^2 + 2414149^2 .
It is a super-2 number, since 2×131000312234022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275007805849 + ... + 3275007805852.
Almost surely, 213100031223402 is an apocalyptic number.
13100031223402 is a deficient number, since it is larger than the sum of its proper divisors (6550015611704).
13100031223402 is an equidigital number, since it uses as much as digits as its factorization.
13100031223402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6550015611703.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 13100031223402 its reverse (20432213000131), we get a palindrome (33532244223533).
The spelling of 13100031223402 in words is "thirteen trillion, one hundred billion, thirty-one million, two hundred twenty-three thousand, four hundred two".
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