1310003210213 has 4 divisors (see below), whose sum is σ = 1311667764000. Its totient is φ = 1308338656428.

The previous prime is 1310003210203. The next prime is 1310003210221. The reversal of 1310003210213 is 3120123000131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310003210213 - 2¹⁶ = 1310003144677 is a prime.

It is a super-2 number, since 2×1310003210213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310003210191 and 1310003210200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310003210203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 832275713 + ... + 832277286.

It is an arithmetic number, because the mean of its divisors is an integer number (327916941000).

Almost surely, 2^{1310003210213} is an apocalyptic number.

It is an amenable number.

1310003210213 is a deficient number, since it is larger than the sum of its proper divisors (1664553787).

1310003210213 is an equidigital number, since it uses as much as digits as its factorization.

1310003210213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1664553786.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1310003210213 its reverse (3120123000131), we get a palindrome (4430126210344).

The spelling of 1310003210213 in words is "one trillion, three hundred ten billion, three million, two hundred ten thousand, two hundred thirteen".