Base | Representation |
---|---|
bin | 11101110010010011100100… |
… | …001110000010101100110010 |
3 | 122011211111202100001022020101 |
4 | 131302103210032002230302 |
5 | 114132302134320224242 |
6 | 1142340415455503014 |
7 | 36410314222346146 |
oct | 3562234416025462 |
9 | 564744670038211 |
10 | 131000331414322 |
11 | 38816a23a03657 |
12 | 128388a9b27a6a |
13 | 58133803ca476 |
14 | 244c642635226 |
15 | 1022944e769b7 |
hex | 7724e4382b32 |
131000331414322 has 4 divisors (see below), whose sum is σ = 196500497121486. Its totient is φ = 65500165707160.
The previous prime is 131000331414311. The next prime is 131000331414361. The reversal of 131000331414322 is 223414133000131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 93277137844081 + 37723193570241 = 9658009^2 + 6141921^2 .
It is a super-2 number, since 2×1310003314143222 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750082853579 + ... + 32750082853582.
Almost surely, 2131000331414322 is an apocalyptic number.
131000331414322 is a deficient number, since it is larger than the sum of its proper divisors (65500165707164).
131000331414322 is an equidigital number, since it uses as much as digits as its factorization.
131000331414322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65500165707163.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 131000331414322 its reverse (223414133000131), we get a palindrome (354414464414453).
The spelling of 131000331414322 in words is "one hundred thirty-one trillion, three hundred thirty-one million, four hundred fourteen thousand, three hundred twenty-two".
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