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131000331414322 = 265500165707161
BaseRepresentation
bin11101110010010011100100…
…001110000010101100110010
3122011211111202100001022020101
4131302103210032002230302
5114132302134320224242
61142340415455503014
736410314222346146
oct3562234416025462
9564744670038211
10131000331414322
1138816a23a03657
12128388a9b27a6a
1358133803ca476
14244c642635226
151022944e769b7
hex7724e4382b32

131000331414322 has 4 divisors (see below), whose sum is σ = 196500497121486. Its totient is φ = 65500165707160.

The previous prime is 131000331414311. The next prime is 131000331414361. The reversal of 131000331414322 is 223414133000131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 93277137844081 + 37723193570241 = 9658009^2 + 6141921^2 .

It is a super-2 number, since 2×1310003314143222 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750082853579 + ... + 32750082853582.

Almost surely, 2131000331414322 is an apocalyptic number.

131000331414322 is a deficient number, since it is larger than the sum of its proper divisors (65500165707164).

131000331414322 is an equidigital number, since it uses as much as digits as its factorization.

131000331414322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65500165707163.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 131000331414322 its reverse (223414133000131), we get a palindrome (354414464414453).

The spelling of 131000331414322 in words is "one hundred thirty-one trillion, three hundred thirty-one million, four hundred fourteen thousand, three hundred twenty-two".

Divisors: 1 2 65500165707161 131000331414322