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131000335 = 5113231859
BaseRepresentation
bin1111100111011…
…10100000001111
3100010111111200021
413303232200033
5232014002320
620555443011
73150325114
oct763564017
9303444607
10131000335
1167a45544
1237a56467
13211a8bbb
141358090b
15b779daa
hex7cee80f

131000335 has 8 divisors (see below), whose sum is σ = 158592240. Its totient is φ = 103872384.

The previous prime is 131000321. The next prime is 131000357. The reversal of 131000335 is 533000131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131000335 - 221 = 128903183 is a prime.

It is a super-2 number, since 2×1310003352 = 34322175540224450, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 115365 + ... + 116494.

It is an arithmetic number, because the mean of its divisors is an integer number (19824030).

Almost surely, 2131000335 is an apocalyptic number.

131000335 is a deficient number, since it is larger than the sum of its proper divisors (27591905).

131000335 is a wasteful number, since it uses less digits than its factorization.

131000335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231977.

The product of its (nonzero) digits is 135, while the sum is 16.

The square root of 131000335 is about 11445.5377767932. The cubic root of 131000335 is about 507.8757407346.

Adding to 131000335 its reverse (533000131), we get a palindrome (664000466).

The spelling of 131000335 in words is "one hundred thirty-one million, three hundred thirty-five", and thus it is an aban number.

Divisors: 1 5 113 565 231859 1159295 26200067 131000335