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13100035 = 513237419
BaseRepresentation
bin110001111110…
…010000000011
3220122112212111
4301332100003
511323200120
61144440151
7216230344
oct61762003
926575774
1013100035
117438283
124479057
132938900
141a500cb
15123b75a
hexc7e403

13100035 has 24 divisors (see below), whose sum is σ = 17524080. Its totient is φ = 9389952.

The previous prime is 13100027. The next prime is 13100039. The reversal of 13100035 is 53000131.

It is not a de Polignac number, because 13100035 - 23 = 13100027 is a prime.

It is a super-2 number, since 2×131000352 = 343221834002450, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a junction number, because it is equal to n+sod(n) for n = 13099988 and 13100024.

It is not an unprimeable number, because it can be changed into a prime (13100039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31056 + ... + 31474.

It is an arithmetic number, because the mean of its divisors is an integer number (730170).

Almost surely, 213100035 is an apocalyptic number.

13100035 is a deficient number, since it is larger than the sum of its proper divisors (4424045).

13100035 is a wasteful number, since it uses less digits than its factorization.

13100035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 487 (or 474 counting only the distinct ones).

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 13100035 is about 3619.3970492335. The cubic root of 13100035 is about 235.7350457032.

Adding to 13100035 its reverse (53000131), we get a palindrome (66100166).

The spelling of 13100035 in words is "thirteen million, one hundred thousand, thirty-five".

Divisors: 1 5 13 37 65 169 185 419 481 845 2095 2405 5447 6253 15503 27235 31265 70811 77515 201539 354055 1007695 2620007 13100035