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131000740128 = 25373750591
BaseRepresentation
bin111101000000001000…
…0001010100100100000
3110112010200000010000000
41322000100022210200
54121242142141003
6140103024300000
712315214630026
oct1720020124440
9415120003000
10131000740128
1150614558a95
122147ba71600
13c47931085b
1464aa36a716
15361ab3e1a3
hex1e8040a920

131000740128 has 192 divisors, whose sum is σ = 397264573440. Its totient is φ = 42485886720.

The previous prime is 131000740127. The next prime is 131000740201. The reversal of 131000740128 is 821047000131.

It is a super-2 number, since 2×1310007401282 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (131000740127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2564113 + ... + 2614703.

It is an arithmetic number, because the mean of its divisors is an integer number (2069086320).

Almost surely, 2131000740128 is an apocalyptic number.

131000740128 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000740128, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198632286720).

131000740128 is an abundant number, since it is smaller than the sum of its proper divisors (266263833312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000740128 is an frugal number, since it uses more digits than its factorization.

131000740128 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50659 (or 50633 counting only the distinct ones).

The product of its (nonzero) digits is 1344, while the sum is 27.

Adding to 131000740128 its reverse (821047000131), we get a palindrome (952047740259).

The spelling of 131000740128 in words is "one hundred thirty-one billion, seven hundred forty thousand, one hundred twenty-eight".