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13100103119 = 76963170213
BaseRepresentation
bin11000011001101001…
…11011010111001111
31020210222011012010102
430030310323113033
5203312111244434
610003524401315
7642430016315
oct141464732717
936728135112
1013100103119
115612737404
12265724623b
13130a05040c
148c3b860b5
1551a12707e
hex30cd3b5cf

13100103119 has 4 divisors (see below), whose sum is σ = 13100350296. Its totient is φ = 13099855944.

The previous prime is 13100103089. The next prime is 13100103131. The reversal of 13100103119 is 91130100131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 91130100131 = 713018585733.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100103119 is a prime.

It is a super-2 number, since 2×131001031192 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13100103119.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100103139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8144 + ... + 162069.

It is an arithmetic number, because the mean of its divisors is an integer number (3275087574).

Almost surely, 213100103119 is an apocalyptic number.

13100103119 is a deficient number, since it is larger than the sum of its proper divisors (247177).

13100103119 is an equidigital number, since it uses as much as digits as its factorization.

13100103119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247176.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 13100103119 in words is "thirteen billion, one hundred million, one hundred three thousand, one hundred nineteen".

Divisors: 1 76963 170213 13100103119