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131001033031403 = 145390159004151
BaseRepresentation
bin11101110010010100001110…
…000010011111111011101011
3122011211120120020021010221012
4131302110032002133323223
5114132310103424001103
61142341013241534135
736410340502114043
oct3562241602377353
9564746506233835
10131001033031403
1138817253a57987
1212838a64aa434b
1358134628848c2
14244c6ab8b0723
1510229868682d8
hex77250e09feeb

131001033031403 has 4 divisors (see below), whose sum is σ = 131091192037008. Its totient is φ = 130910874025800.

The previous prime is 131001033031361. The next prime is 131001033031409. The reversal of 131001033031403 is 304130330100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131001033031403 - 222 = 131001028837099 is a prime.

It is a super-2 number, since 2×1310010330314032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131001033031409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45079500623 + ... + 45079503528.

It is an arithmetic number, because the mean of its divisors is an integer number (32772798009252).

Almost surely, 2131001033031403 is an apocalyptic number.

131001033031403 is a deficient number, since it is larger than the sum of its proper divisors (90159005605).

131001033031403 is an equidigital number, since it uses as much as digits as its factorization.

131001033031403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90159005604.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 131001033031403 its reverse (304130330100131), we get a palindrome (435131363131534).

The spelling of 131001033031403 in words is "one hundred thirty-one trillion, one billion, thirty-three million, thirty-one thousand, four hundred three".

Divisors: 1 1453 90159004151 131001033031403