Base | Representation |
---|---|
bin | 11101110010010100001110… |
… | …011101001000100000000010 |
3 | 122011211120120201101212022111 |
4 | 131302110032131020200002 |
5 | 114132310112220411224 |
6 | 1142341014051325534 |
7 | 36410340615343342 |
oct | 3562241635104002 |
9 | 564746521355274 |
10 | 131001040013314 |
11 | 38817257996559 |
12 | 12838a672b08aa |
13 | 581346415a803 |
14 | 244c6ac7aad22 |
15 | 1022987296d94 |
hex | 77250e748802 |
131001040013314 has 4 divisors (see below), whose sum is σ = 196501560019974. Its totient is φ = 65500520006656.
The previous prime is 131001040013243. The next prime is 131001040013419. The reversal of 131001040013314 is 413310040100131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 72905896865025 + 58095143148289 = 8538495^2 + 7622017^2 .
It is a super-2 number, since 2×1310010400133142 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750260003327 + ... + 32750260003330.
Almost surely, 2131001040013314 is an apocalyptic number.
131001040013314 is a deficient number, since it is larger than the sum of its proper divisors (65500520006660).
131001040013314 is an equidigital number, since it uses as much as digits as its factorization.
131001040013314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65500520006659.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 131001040013314 its reverse (413310040100131), we get a palindrome (544311080113445).
The spelling of 131001040013314 in words is "one hundred thirty-one trillion, one billion, forty million, thirteen thousand, three hundred fourteen".
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