1310011102003 has 4 divisors (see below), whose sum is σ = 1378959054760. Its totient is φ = 1241063149248.

The previous prime is 1310011101937. The next prime is 1310011102061. The reversal of 1310011102003 is 3002011100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310011102003 - 2⁹ = 1310011101491 is a prime.

It is a super-2 number, since 2×1310011102003² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310011102063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34473976350 + ... + 34473976387.

It is an arithmetic number, because the mean of its divisors is an integer number (344739763690).

Almost surely, 2^{1310011102003} is an apocalyptic number.

1310011102003 is a deficient number, since it is larger than the sum of its proper divisors (68947952757).

1310011102003 is an equidigital number, since it uses as much as digits as its factorization.

1310011102003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68947952756.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1310011102003 its reverse (3002011100131), we get a palindrome (4312022202134).

The spelling of 1310011102003 in words is "one trillion, three hundred ten billion, eleven million, one hundred two thousand, three".