1310011102061 has 2 divisors, whose sum is σ = 1310011102062. Its totient is φ = 1310011102060.

The previous prime is 1310011101937. The next prime is 1310011102063. The reversal of 1310011102061 is 1602011100131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1304634546436 + 5376555625 = 1142206^2 + 73325^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310011102061 is a prime.

It is a super-2 number, since 2×1310011102061² (a number of 25 digits) contains 22 as substring.

Together with 1310011102063, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310011102063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655005551030 + 655005551031.

It is an arithmetic number, because the mean of its divisors is an integer number (655005551031).

Almost surely, 2^{1310011102061} is an apocalyptic number.

It is an amenable number.

1310011102061 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310011102061 is an equidigital number, since it uses as much as digits as its factorization.

1310011102061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1310011102061 its reverse (1602011100131), we get a palindrome (2912022202192).

The spelling of 1310011102061 in words is "one trillion, three hundred ten billion, eleven million, one hundred two thousand, sixty-one".