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13100114314 = 27935722451
BaseRepresentation
bin11000011001101001…
…11110000110001010
31020210222011202111001
430030310332012022
5203312112124224
610003524525214
7642430064050
oct141464760612
936728152431
1013100114314
115612744861
12265725080a
13130a055541
148c3b8a1d0
1551a12a544
hex30cd3e18a

13100114314 has 8 divisors (see below), whose sum is σ = 22457338848. Its totient is φ = 5614334700.

The previous prime is 13100114299. The next prime is 13100114317. The reversal of 13100114314 is 41341100131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×131001143142 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100114291 and 13100114300.

It is not an unprimeable number, because it can be changed into a prime (13100114317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 467861212 + ... + 467861239.

It is an arithmetic number, because the mean of its divisors is an integer number (2807167356).

Almost surely, 213100114314 is an apocalyptic number.

13100114314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13100114314 is a deficient number, since it is larger than the sum of its proper divisors (9357224534).

13100114314 is an equidigital number, since it uses as much as digits as its factorization.

13100114314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 935722460.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13100114314 its reverse (41341100131), we get a palindrome (54441214445).

The spelling of 13100114314 in words is "thirteen billion, one hundred million, one hundred fourteen thousand, three hundred fourteen".

Divisors: 1 2 7 14 935722451 1871444902 6550057157 13100114314