131001211300330 has 192 divisors, whose sum is σ = 284306658435072. Its totient is φ = 43304810250240.

The previous prime is 131001211300321. The next prime is 131001211300357. The reversal of 131001211300330 is 33003112100131.

It is a super-2 number, since 2×131001211300330² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001211300298 and 131001211300307.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 655617619 + ... + 655817401.

It is an arithmetic number, because the mean of its divisors is an integer number (1480763846016).

Almost surely, 2^{131001211300330} is an apocalyptic number.

131001211300330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131001211300330 is an abundant number, since it is smaller than the sum of its proper divisors (153305447134742).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001211300330 is a wasteful number, since it uses less digits than its factorization.

131001211300330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200229 (or 200222 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131001211300330 its reverse (33003112100131), we get a palindrome (164004323400461).

The spelling of 131001211300330 in words is "one hundred thirty-one trillion, one billion, two hundred eleven million, three hundred thousand, three hundred thirty".