Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …0100100001111000101111 |
3 | 1201101100200222012120201102 |
4 | 2332220130010201320233 |
5 | 3204113022011432343 |
6 | 43510040153233315 |
7 | 2521311133646216 |
oct | 276503404417057 |
9 | 51340628176642 |
10 | 13100121202223 |
11 | 41a0803998920 |
12 | 1576a8410283b |
13 | 74044a623043 |
14 | 3340991d607d |
15 | 17ab6e3633b8 |
hex | bea1c121e2f |
13100121202223 has 4 divisors (see below), whose sum is σ = 14291041311528. Its totient is φ = 11909201092920.
The previous prime is 13100121202177. The next prime is 13100121202237. The reversal of 13100121202223 is 32220212100131.
13100121202223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13100121202223 - 26 = 13100121202159 is a prime.
It is a super-2 number, since 2×131001212022232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13100121202195 and 13100121202204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100121202253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595460054636 + ... + 595460054657.
It is an arithmetic number, because the mean of its divisors is an integer number (3572760327882).
Almost surely, 213100121202223 is an apocalyptic number.
13100121202223 is a deficient number, since it is larger than the sum of its proper divisors (1190920109305).
13100121202223 is a wasteful number, since it uses less digits than its factorization.
13100121202223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1190920109304.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 13100121202223 its reverse (32220212100131), we get a palindrome (45320333302354).
The spelling of 13100121202223 in words is "thirteen trillion, one hundred billion, one hundred twenty-one million, two hundred two thousand, two hundred twenty-three".
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