13100121211 has 4 divisors (see below), whose sum is σ = 13103726752. Its totient is φ = 13096515672.

The previous prime is 13100121187. The next prime is 13100121233. The reversal of 13100121211 is 11212100131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13100121211 - 2²¹ = 13098024059 is a prime.

It is a super-2 number, since 2×13100121211² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13100121191 and 13100121200.

It is not an unprimeable number, because it can be changed into a prime (13100121611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1797315 + ... + 1804588.

It is an arithmetic number, because the mean of its divisors is an integer number (3275931688).

Almost surely, 2^13100121211 is an apocalyptic number.

13100121211 is a deficient number, since it is larger than the sum of its proper divisors (3605541).

13100121211 is an equidigital number, since it uses as much as digits as its factorization.

13100121211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3605540.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 13100121211 its reverse (11212100131), we get a palindrome (24312221342).

The spelling of 13100121211 in words is "thirteen billion, one hundred million, one hundred twenty-one thousand, two hundred eleven".