Base | Representation |
---|---|
bin | 11101110010010100011110… |
… | …101010101110111111011101 |
3 | 122011211121021200012221112010 |
4 | 131302110132222232333131 |
5 | 114132311141333424201 |
6 | 1142341101045301433 |
7 | 36410350430330211 |
oct | 3562243652567735 |
9 | 564747250187463 |
10 | 131001312014301 |
11 | 38817387486963 |
12 | 12838b22404879 |
13 | 58134a8604341 |
14 | 244c6d6972941 |
15 | 10229a10c4bd6 |
hex | 77251eaaefdd |
131001312014301 has 16 divisors (see below), whose sum is σ = 184943945513088. Its totient is φ = 82196494195200.
The previous prime is 131001312014219. The next prime is 131001312014303. The reversal of 131001312014301 is 103410213100131.
It is not a de Polignac number, because 131001312014301 - 27 = 131001312014173 is a prime.
It is a super-2 number, since 2×1310013120143012 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131001312014303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4192521 + ... + 16720641.
It is an arithmetic number, because the mean of its divisors is an integer number (11558996594568).
Almost surely, 2131001312014301 is an apocalyptic number.
It is an amenable number.
131001312014301 is a deficient number, since it is larger than the sum of its proper divisors (53942633498787).
131001312014301 is a wasteful number, since it uses less digits than its factorization.
131001312014301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12733172.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 131001312014301 its reverse (103410213100131), we get a palindrome (234411525114432).
The spelling of 131001312014301 in words is "one hundred thirty-one trillion, one billion, three hundred twelve million, fourteen thousand, three hundred one".
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