Base | Representation |
---|---|
bin | 11101110010010100011110… |
… | …101100101110001100100100 |
3 | 122011211121021201012102020120 |
4 | 131302110132230232030210 |
5 | 114132311142002112312 |
6 | 1142341101104401540 |
7 | 36410350434630231 |
oct | 3562243654561444 |
9 | 564747251172216 |
10 | 131001312535332 |
11 | 38817387802368 |
12 | 12838b226162b0 |
13 | 58134a8757545 |
14 | 244c6d6a6a788 |
15 | 10229a117928c |
hex | 77251eb2e324 |
131001312535332 has 48 divisors (see below), whose sum is σ = 308399851210752. Its totient is φ = 43277808349440.
The previous prime is 131001312535277. The next prime is 131001312535361. The reversal of 131001312535332 is 233535213100131.
131001312535332 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1310013125353322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131001312535293 and 131001312535302.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43646719 + ... + 46551462.
It is an arithmetic number, because the mean of its divisors is an integer number (6424996900224).
Almost surely, 2131001312535332 is an apocalyptic number.
131001312535332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131001312535332 is an abundant number, since it is smaller than the sum of its proper divisors (177398538675420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131001312535332 is a wasteful number, since it uses less digits than its factorization.
131001312535332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90199268 (or 90199266 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 33.
Adding to 131001312535332 its reverse (233535213100131), we get a palindrome (364536525635463).
The spelling of 131001312535332 in words is "one hundred thirty-one trillion, one billion, three hundred twelve million, five hundred thirty-five thousand, three hundred thirty-two".
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