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131001313522 = 265500656761
BaseRepresentation
bin111101000000001001…
…0010110100011110010
3110112010201002020112211
41322000102112203302
54121242314013042
6140103044442334
712315222535522
oct1720022264362
9415121066484
10131001313522
115061490a872
12214800a93aa
13c479481841
1464aa479682
15361ac04017
hex1e804968f2

131001313522 has 4 divisors (see below), whose sum is σ = 196501970286. Its totient is φ = 65500656760.

The previous prime is 131001313481. The next prime is 131001313571. The reversal of 131001313522 is 225313100131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 127978623081 + 3022690441 = 357741^2 + 54979^2 .

It is a super-2 number, since 2×1310013135222 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001313493 and 131001313502.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750328379 + ... + 32750328382.

Almost surely, 2131001313522 is an apocalyptic number.

131001313522 is a deficient number, since it is larger than the sum of its proper divisors (65500656764).

131001313522 is an equidigital number, since it uses as much as digits as its factorization.

131001313522 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65500656763.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 131001313522 its reverse (225313100131), we get a palindrome (356314413653).

The spelling of 131001313522 in words is "one hundred thirty-one billion, one million, three hundred thirteen thousand, five hundred twenty-two".

Divisors: 1 2 65500656761 131001313522