131001412402103 has 4 divisors (see below), whose sum is σ = 131001453721368. Its totient is φ = 131001371082840.

The previous prime is 131001412402073. The next prime is 131001412402139. The reversal of 131001412402103 is 301204214100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131001412402103 - 2¹² = 131001412398007 is a prime.

It is a super-2 number, since 2×131001412402103² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131001412402193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15469268 + ... + 22389753.

It is an arithmetic number, because the mean of its divisors is an integer number (32750363430342).

Almost surely, 2^{131001412402103} is an apocalyptic number.

131001412402103 is a deficient number, since it is larger than the sum of its proper divisors (41319265).

131001412402103 is an equidigital number, since it uses as much as digits as its factorization.

131001412402103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41319264.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131001412402103 its reverse (301204214100131), we get a palindrome (432205626502234).

The spelling of 131001412402103 in words is "one hundred thirty-one trillion, one billion, four hundred twelve million, four hundred two thousand, one hundred three".