131002121424433 has 16 divisors (see below), whose sum is σ = 154886353937280. Its totient is φ = 108410649774336.

The previous prime is 131002121424431. The next prime is 131002121424533. The reversal of 131002121424433 is 334424121200131.

It is a happy number.

It is not a de Polignac number, because 131002121424433 - 2¹ = 131002121424431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131002121424395 and 131002121424404.

It is not an unprimeable number, because it can be changed into a prime (131002121424431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10073416 + ... + 19065097.

It is an arithmetic number, because the mean of its divisors is an integer number (9680397121080).

Almost surely, 2^{131002121424433} is an apocalyptic number.

It is an amenable number.

131002121424433 is a deficient number, since it is larger than the sum of its proper divisors (23884232512847).

131002121424433 is a wasteful number, since it uses less digits than its factorization.

131002121424433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29160696.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 131002121424433 its reverse (334424121200131), we get a palindrome (465426242624564).

The spelling of 131002121424433 in words is "one hundred thirty-one trillion, two billion, one hundred twenty-one million, four hundred twenty-four thousand, four hundred thirty-three".