13100215403115 has 24 divisors (see below), whose sum is σ = 22742464481568. Its totient is φ = 6975881717760.

The previous prime is 13100215403111. The next prime is 13100215403159. The reversal of 13100215403115 is 51130451200131.

13100215403115 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 0 + 2 + 1 + 540 + 3 + 115 = 666.

It is not a de Polignac number, because 13100215403115 - 2² = 13100215403111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13100215403111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 227050639 + ... + 227108328.

It is an arithmetic number, because the mean of its divisors is an integer number (947602686732).

Almost surely, 2^{13100215403115} is an apocalyptic number.

13100215403115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13100215403115 is a deficient number, since it is larger than the sum of its proper divisors (9642249078453).

13100215403115 is a wasteful number, since it uses less digits than its factorization.

13100215403115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 454159619 (or 454159616 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

Adding to 13100215403115 its reverse (51130451200131), we get a palindrome (64230666603246).

The spelling of 13100215403115 in words is "thirteen trillion, one hundred billion, two hundred fifteen million, four hundred three thousand, one hundred fifteen".