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131002320013 = 383768144531
BaseRepresentation
bin111101000000001011…
…0001100010010001101
3110112010202222101012021
41322000112030102031
54121243043220023
6140103122210141
712315234230065
oct1720026142215
9415122871167
10131002320013
1150615437a84
12214804b3951
13c4797449b6
1464aa65c3a5
15361ad5235d
hex1e8058c48d

131002320013 has 8 divisors (see below), whose sum is σ = 131364412416. Its totient is φ = 130640332800.

The previous prime is 131002319963. The next prime is 131002320019. The reversal of 131002320013 is 310023200131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131002320013 - 221 = 131000222861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131002320019) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2919558 + ... + 2964088.

It is an arithmetic number, because the mean of its divisors is an integer number (16420551552).

Almost surely, 2131002320013 is an apocalyptic number.

It is an amenable number.

131002320013 is a deficient number, since it is larger than the sum of its proper divisors (362092403).

131002320013 is an equidigital number, since it uses as much as digits as its factorization.

131002320013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52595.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 131002320013 its reverse (310023200131), we get a palindrome (441025520144).

The spelling of 131002320013 in words is "one hundred thirty-one billion, two million, three hundred twenty thousand, thirteen".

Divisors: 1 383 7681 44531 2941823 17055373 342042611 131002320013