1310023424203 has 4 divisors (see below), whose sum is σ = 1410794456848. Its totient is φ = 1209252391560.

The previous prime is 1310023424201. The next prime is 1310023424233. The reversal of 1310023424203 is 3024243200131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310023424203 - 2¹ = 1310023424201 is a prime.

It is a super-2 number, since 2×1310023424203² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310023424201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50385516303 + ... + 50385516328.

It is an arithmetic number, because the mean of its divisors is an integer number (352698614212).

Almost surely, 2^{1310023424203} is an apocalyptic number.

1310023424203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1310023424203 is a deficient number, since it is larger than the sum of its proper divisors (100771032645).

1310023424203 is a wasteful number, since it uses less digits than its factorization.

1310023424203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100771032644.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1310023424203 its reverse (3024243200131), we get a palindrome (4334266624334).

The spelling of 1310023424203 in words is "one trillion, three hundred ten billion, twenty-three million, four hundred twenty-four thousand, two hundred three".