13100234321133 has 12 divisors (see below), whose sum is σ = 19047875659488. Its totient is φ = 8675651867400.

The previous prime is 13100234321099. The next prime is 13100234321149. The reversal of 13100234321133 is 33112343200131.

13100234321133 is a `hidden beast` number, since 1 + 3 + 100 + 2 + 343 + 211 + 3 + 3 = 666.

13100234321133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13100234321133 - 2¹⁷ = 13100234190061 is a prime.

It is a super-2 number, since 2×13100234321133² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13100234321097 and 13100234321106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100234321173) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4819805235 + ... + 4819807952.

It is an arithmetic number, because the mean of its divisors is an integer number (1587322971624).

Almost surely, 2^{13100234321133} is an apocalyptic number.

It is an amenable number.

13100234321133 is a deficient number, since it is larger than the sum of its proper divisors (5947641338355).

13100234321133 is a wasteful number, since it uses less digits than its factorization.

13100234321133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9639613344 (or 9639613341 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 13100234321133 its reverse (33112343200131), we get a palindrome (46212577521264).

The spelling of 13100234321133 in words is "thirteen trillion, one hundred billion, two hundred thirty-four million, three hundred twenty-one thousand, one hundred thirty-three".