1310031112231 has 4 divisors (see below), whose sum is σ = 1316681016552. Its totient is φ = 1303381207912.

The previous prime is 1310031112207. The next prime is 1310031112259. The reversal of 1310031112231 is 1322111300131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310031112231 - 2⁵ = 1310031112199 is a prime.

It is a super-2 number, since 2×1310031112231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310031112199 and 1310031112208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310031112331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3324951865 + ... + 3324952258.

It is an arithmetic number, because the mean of its divisors is an integer number (329170254138).

Almost surely, 2^{1310031112231} is an apocalyptic number.

1310031112231 is a deficient number, since it is larger than the sum of its proper divisors (6649904321).

1310031112231 is an equidigital number, since it uses as much as digits as its factorization.

1310031112231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6649904320.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1310031112231 its reverse (1322111300131), we get a palindrome (2632142412362).

The spelling of 1310031112231 in words is "one trillion, three hundred ten billion, thirty-one million, one hundred twelve thousand, two hundred thirty-one".