Base | Representation |
---|---|
bin | 10011000100000011111… |
… | …111100010001101011010 |
3 | 11122020102101100110201200 |
4 | 103010003333202031122 |
5 | 132430421143341442 |
6 | 2441453112255030 |
7 | 163434546242211 |
oct | 23040377421532 |
9 | 4566371313650 |
10 | 1310032012122 |
11 | 465643a113a9 |
12 | 191a870a1476 |
13 | 966c66126a2 |
14 | 47597a82078 |
15 | 24124a0834c |
hex | 13103fe235a |
1310032012122 has 48 divisors (see below), whose sum is σ = 2854075730688. Its totient is φ = 434270148480.
The previous prime is 1310032012109. The next prime is 1310032012151. The reversal of 1310032012122 is 2212102300131.
1310032012122 is a `hidden beast` number, since 1 + 310 + 0 + 320 + 12 + 1 + 22 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 1310032012095 and 1310032012104.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3729538 + ... + 4065650.
It is an arithmetic number, because the mean of its divisors is an integer number (59459911056).
Almost surely, 21310032012122 is an apocalyptic number.
1310032012122 is an abundant number, since it is smaller than the sum of its proper divisors (1544043718566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310032012122 is a wasteful number, since it uses less digits than its factorization.
1310032012122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 337315 (or 337312 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1310032012122 its reverse (2212102300131), we get a palindrome (3522134312253).
The spelling of 1310032012122 in words is "one trillion, three hundred ten billion, thirty-two million, twelve thousand, one hundred twenty-two".
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