Base | Representation |
---|---|
bin | 111101000000001100… |
… | …1100100000110101011 |
3 | 110112010211122021210221 |
4 | 1322000121210012223 |
5 | 4121243310012021 |
6 | 140103153150511 |
7 | 12315244601251 |
oct | 1720031440653 |
9 | 415124567727 |
10 | 131003204011 |
11 | 50615991159 |
12 | 2148085b437 |
13 | c479994184 |
14 | 64aa80c5d1 |
15 | 361ae79241 |
hex | 1e806641ab |
131003204011 has 8 divisors (see below), whose sum is σ = 134016151104. Its totient is φ = 127999658880.
The previous prime is 131003204009. The next prime is 131003204077. The reversal of 131003204011 is 110402300131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131003204011 - 21 = 131003204009 is a prime.
It is a super-2 number, since 2×1310032040112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131003204081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2322300 + ... + 2378041.
It is an arithmetic number, because the mean of its divisors is an integer number (16752018888).
Almost surely, 2131003204011 is an apocalyptic number.
131003204011 is a deficient number, since it is larger than the sum of its proper divisors (3012947093).
131003204011 is an equidigital number, since it uses as much as digits as its factorization.
131003204011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4700981.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 131003204011 its reverse (110402300131), we get a palindrome (241405504142).
The spelling of 131003204011 in words is "one hundred thirty-one billion, three million, two hundred four thousand, eleven".
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