Base | Representation |
---|---|
bin | 1011111010100010011111… |
… | …1111001010000010100111 |
3 | 1201101101012220101110221012 |
4 | 2332220213333022002213 |
5 | 3204113424201323143 |
6 | 43510112054212435 |
7 | 2521316112143135 |
oct | 276504777120247 |
9 | 51341186343835 |
10 | 13100321120423 |
11 | 41a08a6825379 |
12 | 1576b1b05411b |
13 | 74047cb7c034 |
14 | 3340b7996755 |
15 | 17ab81ba3418 |
hex | bea27fca0a7 |
13100321120423 has 4 divisors (see below), whose sum is σ = 13103397039480. Its totient is φ = 13097245201368.
The previous prime is 13100321120417. The next prime is 13100321120449. The reversal of 13100321120423 is 32402112300131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13100321120423 - 28 = 13100321120167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100321120723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1537953140 + ... + 1537961657.
It is an arithmetic number, because the mean of its divisors is an integer number (3275849259870).
Almost surely, 213100321120423 is an apocalyptic number.
13100321120423 is a deficient number, since it is larger than the sum of its proper divisors (3075919057).
13100321120423 is an equidigital number, since it uses as much as digits as its factorization.
13100321120423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3075919056.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13100321120423 its reverse (32402112300131), we get a palindrome (45502433420554).
The spelling of 13100321120423 in words is "thirteen trillion, one hundred billion, three hundred twenty-one million, one hundred twenty thousand, four hundred twenty-three".
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