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131003211300 = 2235213211397401
BaseRepresentation
bin111101000000001100…
…1100101111000100100
3110112010211122122210220
41322000121211320210
54121243310230200
6140103153244340
712315244631433
oct1720031457044
9415124578726
10131003211300
1150615996685
12214808636b0
13c4799975a0
1464aa81111a
15361ae7b4a0
hex1e80665e24

131003211300 has 288 divisors, whose sum is σ = 412185535104. Its totient is φ = 31933440000.

The previous prime is 131003211257. The next prime is 131003211341. The reversal of 131003211300 is 3112300131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 131003211300.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 326691100 + ... + 326691500.

Almost surely, 2131003211300 is an apocalyptic number.

131003211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131003211300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (206092767552).

131003211300 is an abundant number, since it is smaller than the sum of its proper divisors (281182323804).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131003211300 is a wasteful number, since it uses less digits than its factorization.

131003211300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1039 (or 1032 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 131003211300 its reverse (3112300131), we get a palindrome (134115511431).

The spelling of 131003211300 in words is "one hundred thirty-one billion, three million, two hundred eleven thousand, three hundred".