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131003424103 = 139942470677
BaseRepresentation
bin111101000000001101…
…0011001110101100111
3110112010212001110201111
41322000122121311213
54121243334032403
6140103202005451
712315246506026
oct1720032316547
9415125043644
10131003424103
1150616021552
1221480946887
13c479a403c6
1464aa8688bd
15361aebe56d
hex1e80699d67

131003424103 has 4 divisors (see below), whose sum is σ = 131945894920. Its totient is φ = 130060953288.

The previous prime is 131003424067. The next prime is 131003424109. The reversal of 131003424103 is 301424300131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131003424103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131003424109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471235200 + ... + 471235477.

It is an arithmetic number, because the mean of its divisors is an integer number (32986473730).

Almost surely, 2131003424103 is an apocalyptic number.

131003424103 is a deficient number, since it is larger than the sum of its proper divisors (942470817).

131003424103 is an equidigital number, since it uses as much as digits as its factorization.

131003424103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 942470816.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 131003424103 its reverse (301424300131), we get a palindrome (432427724234).

The spelling of 131003424103 in words is "one hundred thirty-one billion, three million, four hundred twenty-four thousand, one hundred three".

Divisors: 1 139 942470677 131003424103