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13100344343401 = 71871477763343
BaseRepresentation
bin1011111010100010100101…
…0111101111101101101001
31201101101021112002022212111
42332220221113233231221
53204114001122442101
643510114244042321
72521316513424460
oct276505127575551
951341245068774
1013100344343401
1141a0908947117
121576b269933a1
13740484920443
143340baabd9d7
1517ab83c3e251
hexbea295efb69

13100344343401 has 4 divisors (see below), whose sum is σ = 14971822106752. Its totient is φ = 11228866580052.

The previous prime is 13100344343399. The next prime is 13100344343419. The reversal of 13100344343401 is 10434344300131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100344343401 - 21 = 13100344343399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13100344353401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 935738881665 + ... + 935738881678.

It is an arithmetic number, because the mean of its divisors is an integer number (3742955526688).

Almost surely, 213100344343401 is an apocalyptic number.

It is an amenable number.

13100344343401 is a deficient number, since it is larger than the sum of its proper divisors (1871477763351).

13100344343401 is an equidigital number, since it uses as much as digits as its factorization.

13100344343401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1871477763350.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13100344343401 its reverse (10434344300131), we get a palindrome (23534688643532).

The spelling of 13100344343401 in words is "thirteen trillion, one hundred billion, three hundred forty-four million, three hundred forty-three thousand, four hundred one".

Divisors: 1 7 1871477763343 13100344343401