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13100353421 = 67195527663
BaseRepresentation
bin11000011001101011…
…11000011110001101
31020210222121220110212
430030311320132031
5203312142302141
610003534012205
7642432111131
oct141465703615
936728556425
1013100353421
115612898471
122657347065
13130a10a31c
148c3c0d3c1
1551a1762eb
hex30cd7878d

13100353421 has 4 divisors (see below), whose sum is σ = 13295881152. Its totient is φ = 12904825692.

The previous prime is 13100353373. The next prime is 13100353423. The reversal of 13100353421 is 12435300131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100353421 - 226 = 13033244557 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100353423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97763765 + ... + 97763898.

It is an arithmetic number, because the mean of its divisors is an integer number (3323970288).

Almost surely, 213100353421 is an apocalyptic number.

It is an amenable number.

13100353421 is a deficient number, since it is larger than the sum of its proper divisors (195527731).

13100353421 is an equidigital number, since it uses as much as digits as its factorization.

13100353421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 195527730.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 13100353421 its reverse (12435300131), we get a palindrome (25535653552).

The spelling of 13100353421 in words is "thirteen billion, one hundred million, three hundred fifty-three thousand, four hundred twenty-one".

Divisors: 1 67 195527663 13100353421