13100402120101 has 4 divisors (see below), whose sum is σ = 13102125184672. Its totient is φ = 13098679055532.

The previous prime is 13100402120083. The next prime is 13100402120111. The reversal of 13100402120101 is 10102120400131.

13100402120101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100402120101 - 2²¹ = 13100400022949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100402120111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 861520881 + ... + 861536086.

It is an arithmetic number, because the mean of its divisors is an integer number (3275531296168).

Almost surely, 2^{13100402120101} is an apocalyptic number.

It is an amenable number.

13100402120101 is a deficient number, since it is larger than the sum of its proper divisors (1723064571).

13100402120101 is an equidigital number, since it uses as much as digits as its factorization.

13100402120101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1723064570.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13100402120101 its reverse (10102120400131), we get a palindrome (23202522520232).

The spelling of 13100402120101 in words is "thirteen trillion, one hundred billion, four hundred two million, one hundred twenty thousand, one hundred one".