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1310089015007 = 12744710279481
BaseRepresentation
bin10011000100000111011…
…000111110111011011111
311122020120100121111222122
4103010013120332323133
5132431030241440012
62441502510133155
7163436140614323
oct23040730767337
94566510544878
101310089015007
11465673105523
12191aa21b11bb
13967053803c6
14475a147d983
1524129a17e72
hex1310763eedf

1310089015007 has 4 divisors (see below), whose sum is σ = 1310099421936. Its totient is φ = 1310078608080.

The previous prime is 1310089014979. The next prime is 1310089015043. The reversal of 1310089015007 is 7005109800131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310089015007 - 214 = 1310088998623 is a prime.

It is a super-2 number, since 2×13100890150072 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310089012007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5012294 + ... + 5267187.

It is an arithmetic number, because the mean of its divisors is an integer number (327524855484).

Almost surely, 21310089015007 is an apocalyptic number.

1310089015007 is a deficient number, since it is larger than the sum of its proper divisors (10406929).

1310089015007 is a wasteful number, since it uses less digits than its factorization.

1310089015007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10406928.

The product of its (nonzero) digits is 7560, while the sum is 35.

The spelling of 1310089015007 in words is "one trillion, three hundred ten billion, eighty-nine million, fifteen thousand, seven".

Divisors: 1 127447 10279481 1310089015007