Base | Representation |
---|---|
bin | 11000011001110000… |
… | …10110101001101011 |
3 | 1020211000211211020020 |
4 | 30030320112221223 |
5 | 203312324020243 |
6 | 10003555531523 |
7 | 642440450064 |
oct | 141470265153 |
9 | 36730754206 |
10 | 13101001323 |
11 | 56131a0223 |
12 | 26575b9ba3 |
13 | 130a2a61b7 |
14 | 8c3d3b56b |
15 | 51a253283 |
hex | 30ce16a6b |
13101001323 has 8 divisors (see below), whose sum is σ = 17839661568. Its totient is φ = 8548170984.
The previous prime is 13101001321. The next prime is 13101001327. The reversal of 13101001323 is 32310010131.
13101001323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13101001323 - 21 = 13101001321 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13101001321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46457311 + ... + 46457592.
It is an arithmetic number, because the mean of its divisors is an integer number (2229957696).
Almost surely, 213101001323 is an apocalyptic number.
13101001323 is a deficient number, since it is larger than the sum of its proper divisors (4738660245).
13101001323 is an equidigital number, since it uses as much as digits as its factorization.
13101001323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 92914953.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 13101001323 its reverse (32310010131), we get a palindrome (45411011454).
The spelling of 13101001323 in words is "thirteen billion, one hundred one million, one thousand, three hundred twenty-three".
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