Search a number
-
+
13101003131 = 17770647243
BaseRepresentation
bin11000011001110000…
…10111000101111011
31020211000211220201012
430030320113011323
5203312324100011
610003555544135
7642440455256
oct141470270573
936730756635
1013101003131
1156131a1617
1226575bb04b
13130a2a6c78
148c3d3c09d
1551a253a8b
hex30ce1717b

13101003131 has 4 divisors (see below), whose sum is σ = 13871650392. Its totient is φ = 12330355872.

The previous prime is 13101003127. The next prime is 13101003137. The reversal of 13101003131 is 13130010131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101003131 - 22 = 13101003127 is a prime.

It is a super-2 number, since 2×131010031312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101003137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385323605 + ... + 385323638.

It is an arithmetic number, because the mean of its divisors is an integer number (3467912598).

Almost surely, 213101003131 is an apocalyptic number.

13101003131 is a deficient number, since it is larger than the sum of its proper divisors (770647261).

13101003131 is an equidigital number, since it uses as much as digits as its factorization.

13101003131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 770647260.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 13101003131 its reverse (13130010131), we get a palindrome (26231013262).

The spelling of 13101003131 in words is "thirteen billion, one hundred one million, three thousand, one hundred thirty-one".

Divisors: 1 17 770647243 13101003131