13101011311 has 4 divisors (see below), whose sum is σ = 13163101624. Its totient is φ = 13038921000.

The previous prime is 13101011303. The next prime is 13101011317. The reversal of 13101011311 is 11311010131.

13101011311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11311010131 = 29333 ⋅385607.

It is a cyclic number.

It is not a de Polignac number, because 13101011311 - 2³ = 13101011303 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101011291 and 13101011300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101011317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31044840 + ... + 31045261.

It is an arithmetic number, because the mean of its divisors is an integer number (3290775406).

Almost surely, 2^13101011311 is an apocalyptic number.

13101011311 is a deficient number, since it is larger than the sum of its proper divisors (62090313).

13101011311 is an equidigital number, since it uses as much as digits as its factorization.

13101011311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62090312.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 13101011311 its reverse (11311010131), we get a palindrome (24412021442).

The spelling of 13101011311 in words is "thirteen billion, one hundred one million, eleven thousand, three hundred eleven".