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131010220003034 = 265505110001517
BaseRepresentation
bin11101110010011100110001…
…101000000000111011011010
3122011212110021111011122210202
4131302130301220000323122
5114132432412310044114
61142345133022342202
736411114245100641
oct3562346150007332
9564773244148722
10131010220003034
1138820138842719
121283a7a972a962
135814297caa0a8
14244ccdda76358
151022d23178cde
hex772731a00eda

131010220003034 has 4 divisors (see below), whose sum is σ = 196515330004554. Its totient is φ = 65505110001516.

The previous prime is 131010220003007. The next prime is 131010220003037. The reversal of 131010220003034 is 430300022010131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 91709294791009 + 39300925212025 = 9576497^2 + 6269045^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131010220002997 and 131010220003015.

It is not an unprimeable number, because it can be changed into a prime (131010220003037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32752555000757 + ... + 32752555000760.

Almost surely, 2131010220003034 is an apocalyptic number.

131010220003034 is a deficient number, since it is larger than the sum of its proper divisors (65505110001520).

131010220003034 is an equidigital number, since it uses as much as digits as its factorization.

131010220003034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65505110001519.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 131010220003034 its reverse (430300022010131), we get a palindrome (561310242013165).

The spelling of 131010220003034 in words is "one hundred thirty-one trillion, ten billion, two hundred twenty million, three thousand, thirty-four".

Divisors: 1 2 65505110001517 131010220003034