13101034002143 has 4 divisors (see below), whose sum is σ = 13101145114848. Its totient is φ = 13100922889440.

The previous prime is 13101034002137. The next prime is 13101034002181. The reversal of 13101034002143 is 34120043010131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101034002143 - 2⁴ = 13101034002127 is a prime.

It is a super-4 number, since 4×13101034002143⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101034007143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55379303 + ... + 55615368.

It is an arithmetic number, because the mean of its divisors is an integer number (3275286278712).

Almost surely, 2^{13101034002143} is an apocalyptic number.

13101034002143 is a deficient number, since it is larger than the sum of its proper divisors (111112705).

13101034002143 is a wasteful number, since it uses less digits than its factorization.

13101034002143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 111112704.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13101034002143 its reverse (34120043010131), we get a palindrome (47221077012274).

The spelling of 13101034002143 in words is "thirteen trillion, one hundred one billion, thirty-four million, two thousand, one hundred forty-three".