Base | Representation |
---|---|
bin | 11101110010011100111101… |
… | …000101010110000111111001 |
3 | 122011212110202212220101021021 |
4 | 131302130331011112013321 |
5 | 114132433311013211101 |
6 | 1142345204050542441 |
7 | 36411122101100440 |
oct | 3562347505260771 |
9 | 564773685811237 |
10 | 131010412241401 |
11 | 38820227304200 |
12 | 1283a841b97a21 |
13 | 58142c8a775c4 |
14 | 244cd1b3d7d57 |
15 | 1022d34e9d5a1 |
hex | 77273d1561f9 |
131010412241401 has 12 divisors (see below), whose sum is σ = 164575063312576. Its totient is φ = 102086035512120.
The previous prime is 131010412241389. The next prime is 131010412241417. The reversal of 131010412241401 is 104142214010131.
It is not a de Polignac number, because 131010412241401 - 223 = 131010403852793 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131010412241431) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 77337904845 + ... + 77337906538.
Almost surely, 2131010412241401 is an apocalyptic number.
131010412241401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131010412241401 is a deficient number, since it is larger than the sum of its proper divisors (33564651071175).
131010412241401 is a wasteful number, since it uses less digits than its factorization.
131010412241401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154675811412 (or 154675811401 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 131010412241401 its reverse (104142214010131), we get a palindrome (235152626251532).
The spelling of 131010412241401 in words is "one hundred thirty-one trillion, ten billion, four hundred twelve million, two hundred forty-one thousand, four hundred one".
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