131010441311 has 4 divisors (see below), whose sum is σ = 131011352112. Its totient is φ = 131009530512.

The previous prime is 131010441283. The next prime is 131010441329. The reversal of 131010441311 is 113144010131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 113144010131 = 73 ⋅1549917947.

It is a cyclic number.

It is not a de Polignac number, because 131010441311 - 2¹⁰ = 131010440287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010401311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186851 + ... + 544916.

It is an arithmetic number, because the mean of its divisors is an integer number (32752838028).

Almost surely, 2^131010441311 is an apocalyptic number.

131010441311 is a deficient number, since it is larger than the sum of its proper divisors (910801).

131010441311 is an equidigital number, since it uses as much as digits as its factorization.

131010441311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 910800.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131010441311 its reverse (113144010131), we get a palindrome (244154451442).

The spelling of 131010441311 in words is "one hundred thirty-one billion, ten million, four hundred forty-one thousand, three hundred eleven".