131011120342143 has 12 divisors (see below), whose sum is σ = 191075549842320. Its totient is φ = 86492778477696.

The previous prime is 131011120342129. The next prime is 131011120342147. The reversal of 131011120342143 is 341243021110131.

131011120342143 is a `hidden beast` number, since 1 + 31 + 0 + 1 + 1 + 1 + 203 + 421 + 4 + 3 = 666.

It is not a de Polignac number, because 131011120342143 - 2¹⁷ = 131011120211071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131011120342147) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 70664033778 + ... + 70664035631.

It is an arithmetic number, because the mean of its divisors is an integer number (15922962486860).

Almost surely, 2^{131011120342143} is an apocalyptic number.

131011120342143 is a deficient number, since it is larger than the sum of its proper divisors (60064429500177).

131011120342143 is a wasteful number, since it uses less digits than its factorization.

131011120342143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141328069518 (or 141328069515 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 131011120342143 its reverse (341243021110131), we get a palindrome (472254141452274).

The spelling of 131011120342143 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty million, three hundred forty-two thousand, one hundred forty-three".