13101113 has 4 divisors (see below), whose sum is σ = 13296720. Its totient is φ = 12905508.

The previous prime is 13101097. The next prime is 13101119. The reversal of 13101113 is 31110131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101113 - 2⁴ = 13101097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101094 and 13101103.

It is not an unprimeable number, because it can be changed into a prime (13101119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97703 + ... + 97836.

It is an arithmetic number, because the mean of its divisors is an integer number (3324180).

Almost surely, 2^13101113 is an apocalyptic number.

It is an amenable number.

13101113 is a deficient number, since it is larger than the sum of its proper divisors (195607).

13101113 is an equidigital number, since it uses as much as digits as its factorization.

13101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195606.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 13101113 is about 3619.5459660018. The cubic root of 13101113 is about 235.7415117268.

Adding to 13101113 its reverse (31110131), we get a palindrome (44211244).

The spelling of 13101113 in words is "thirteen million, one hundred one thousand, one hundred thirteen".